ihuangweiwei 发表于 2013-1-12 13:26:24

MongoDB语法与MySql语法比较

MongoDB语法                                 MySql语法db.test.find({'name':'foobar'}) <==> select * from test where name='foobar'db.test.find()                            <==> select * from testdb.test.find({'ID':10}).count() <==> select count(*) from test where ID=10db.test.find().skip(10).limit(20) <==> select * from test limit 10,20db.test.find({'ID':{$in:}}) <==> select * from test where ID in (25,35,45)db.test.find().sort({'ID':-1})<==> select * from test order by ID descdb.test.distinct('name',{'ID':{$lt:20}})<==> select distinct(name) from test where ID<20db.test.group({key:{'name':true},cond:{'name':'foo'},reduce:function(obj,prev){prev.msum+=obj.marks;},initial:{msum:0}})<==> select name,sum(marks) from test group by namedb.test.find('this.ID<20',{name:1})<==> select name from test where ID<20db.test.insert({'name':'foobar','age':25})<==>insert into test ('name','age') values('foobar',25)db.test.remove({})                        <==> delete * from testdb.test.remove({'age':20})            <==> delete test where age=20db.test.remove({'age':{$lt:20}})   <==> elete test where age<20db.test.remove({'age':{$lte:20}})<==> delete test where age<=20db.test.remove({'age':{$gt:20}})<==> delete test where age>20db.test.remove({'age':{$gte:20}}) <==> delete test where age>=20db.test.remove({'age':{$ne:20}})<==> delete test where age!=20db.test.update({'name':'foobar'},{$set:{'age':36}}) <==> update test set age=36 where name='foobar'db.test.update({'name':'foobar'},{$inc:{'age':3}}) <==> update test set age=age+3 where name='foobar' 
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