php数组相加:array(“a”)+array(“b”)结果还是array(“a”)
php数组相加:array(“a”)+array(“b”)结果还是array(“a”)<div id="cnblogs_post_body">在网上看到一道题:
array(&ldquo;a&rdquo;)+array(&ldquo;b&rdquo;)的结果是___
A.array(&ldquo;a&rdquo;,&rdquo;b&rdquo;)
B.array(&ldquo;b&rdquo;,&rdquo;a&rdquo;)
C.array(&ldquo;b&rdquo;)
D.array(&ldquo;a&rdquo;)
答案:D
php两个数组相加,为什么结果还是不变呢?
因为,它们等效于array(&ldquo;0&Prime;=>&rdquo;a&rdquo;)+array(&ldquo;0&Prime;=>&rdquo;b&rdquo;),它们的键名相同,前者不能被后者覆盖,如果是array(&ldquo;0&Prime;=>&rdquo;a&rdquo;)+array(&ldquo;0&Prime;=>&rdquo;b&rdquo;,&rdquo;1&Prime;=>&rdquo;c&rdquo;),那么结果等于array(&ldquo;0&Prime;=>&rdquo;a&rdquo;,&rdquo;1&Prime;=>&rdquo;c&rdquo;)
如果是同一个数组里面,有相同的键名会出现什么情况?
看一段php官方手册中的代码:
<div class="cnblogs_Highlighter">$switching = array( 10, // key = 0 5 =>6, 3 =>7, 'a'=>4, 11, // key = 6 (maximum of integer-indices was 5) '8'=>2, // key = 8 (integer!) '02' => 77, // key = '02' 0 => 12// the value 10 will be overwritten by 12 );
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