Convert a String of hexademical digits into a Int
<<The C programming language>> has an Exercise.Converta String of hexademical digits into a Int.
#include <stdio.h>int hexaDecimalToDecimal(char s[]){if(s!='0') return -1;if(s!='X' && s!='x') return -1;int i=2;int sum=0;while(s!='\0'){ if(s>='a' && s<='f')s=s-'a'+10;else if(s>='A' && s<='F')s=s-'A'+10;else if(s>='0' && s<='9')s=s-'0';sum=sum*16+s;i++;}return sum;}int main(){char s[]="0xb1A";printf("%s",s);printf(" 十进制为:%d\n",hexaDecimalToDecimal(s));printf("%d",0xb1a);}
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