计算GPS WGS_84 两点的距离 更加细腻的算法
<div id="cnblogs_post_body">上面的一篇博客，两点距离比较粗糙，现贴一篇更加细腻的算法<div class="cnblogs_Highlighter">wgs84PointsDistance = function(fromPoint, toPoint) {if(arguments.length != 2) {return 0;}lon1 = fromPoint.x;lat1 = fromPoint.y;lon2 = toPoint.x;lat2 = toPoint.y;var a = 6378137, b = 6356752.3142, f = 1 / 298.257223563;var L = (lon2 - lon1).toRad();var U1 = Math.atan((1 - f) * Math.tan(lat1.toRad()));var U2 = Math.atan((1 - f) * Math.tan(lat2.toRad()));var sinU1 = Math.sin(U1), cosU1 = Math.cos(U1);var sinU2 = Math.sin(U2), cosU2 = Math.cos(U2);var lambda = L, lambdaP, iterLimit = 100;do {var sinLambda = Math.sin(lambda), cosLambda = Math.cos(lambda);var sinSigma = Math.sqrt((cosU2 * sinLambda) * (cosU2 * sinLambda) + (cosU1 * sinU2 - sinU1 * cosU2 * cosLambda) * (cosU1 * sinU2 - sinU1 * cosU2 * cosLambda));if(sinSigma == 0)return 0;var cosSigma = sinU1 * sinU2 + cosU1 * cosU2 * cosLambda;var sigma = Math.atan2(sinSigma, cosSigma);var sinAlpha = cosU1 * cosU2 * sinLambda / sinSigma;var cosSqAlpha = 1 - sinAlpha * sinAlpha;var cos2SigmaM = cosSigma - 2 * sinU1 * sinU2 / cosSqAlpha;if(isNaN(cos2SigmaM))cos2SigmaM = 0;var C = f / 16 * cosSqAlpha * (4 + f * (4 - 3 * cosSqAlpha));lambdaP = lambda;lambda = L + (1 - C) * f * sinAlpha * (sigma + C * sinSigma * (cos2SigmaM + C * cosSigma * (-1 + 2 * cos2SigmaM * cos2SigmaM))); } while (Math.abs(lambda-lambdaP) > (1e-12) && --iterLimit>0);if(iterLimit == 0) {return NaN}var uSq = cosSqAlpha * (a * a - b * b) / (b * b);var A = 1 + uSq / 16384 * (4096 + uSq * (-768 + uSq * (320 - 175 * uSq)));var B = uSq / 1024 * (256 + uSq * (-128 + uSq * (74 - 47 * uSq)));var deltaSigma = B * sinSigma * (cos2SigmaM + B / 4 * (cosSigma * (-1 + 2 * cos2SigmaM * cos2SigmaM) - B / 6 * cos2SigmaM * (-3 + 4 * sinSigma * sinSigma) * (-3 + 4 * cos2SigmaM * cos2SigmaM)));var s = b * A * (sigma - deltaSigma);var fwdAz = Math.atan2(cosU2 * sinLambda, cosU1 * sinU2 - sinU1 * cosU2 * cosLambda);var revAz = Math.atan2(cosU1 * sinLambda, -sinU1 * cosU2 + cosU1 * sinU2 * cosLambda);return s;}
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