python轻松去除 list 重复元素
比较容易记忆的是用内置的setl1 = ['b','c','d','b','c','a','a']l2 = list(set(l1))print l2
还有一种据说速度更快的，没测试过两者的速度差别
l1 = ['b','c','d','b','c','a','a']l2 = {}.fromkeys(l1).keys()print l2
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这两种都有个缺点，祛除重复元素后排序变了：
['a', 'c', 'b', 'd']
如果想要保持他们原来的排序：
用list类的sort方法
l1 = ['b','c','d','b','c','a','a']l2 = list(set(l1))l2.sort(key=l1.index)print l2
也可以这样写
l1 = ['b','c','d','b','c','a','a']
l2 = sorted(set(l1),key=l1.index)
print l2
也可以用遍历
l1 = ['b','c','d','b','c','a','a']l2 = []for i in l1: if not i in l2: l2.append(i)print l2
上面的代码也可以这样写
l1 = ['b','c','d','b','c','a','a']l2 = []print l2
这样就可以保证排序不变了：
['b', 'c', 'd', 'a']
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