hudingchen 发表于 2013-1-29 22:22:08

使用hash join 优化 sql

低效:
SELECT a.*,       b.object_nameFROM TEST_OBJECT a,       TEST_OBJ1   b WHERE SUBSTR(a.object_name, 1, LENGTH(b.object_name)) = b.object_name;
実行計画
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=ALL_ROWS (Cost=26 Card=67 Bytes=2077)
   1    0   NESTED LOOPS (Cost=26 Card=67 Bytes=2077)
   2    1   TABLE ACCESS (FULL) OF 'TEST_OBJECT' (TABLE) (Cost=2 Card=82 Bytes=1558)
   3    1   TABLE ACCESS (FULL) OF 'TEST_OBJ1' (TABLE) (Cost=0 Card=1 Bytes=12)

高效:
SELECT a.*,       b.object_nameFROM TEST_OBJECT a,       TEST_OBJ1   b WHERE    SUBSTR(a.object_name, 1, LENGTH(b.object_name)) = b.object_name   SUBSTR(a.object_name, 1, 4) = SUBSTR(b.object_name, 1, 4)--hash join   AND LENGTH(b.object_name) > 3UNION ALLSELECT a.*,       b.object_nameFROM TEST_OBJECT a,       TEST_OBJ1   b WHERE SUBSTR(a.object_name, 1, LENGTH(b.object_name)) = b.object_name   AND LENGTH(b.object_name) < 4;
実行計画
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=ALL_ROWS (Cost=10 Card=4 Bytes=124)
   1    0   UNION-ALL
   2    1   HASH JOIN (Cost=5 Card=1 Bytes=31)
   3    2       TABLE ACCESS (FULL) OF 'TEST_OBJ1' (TABLE) (Cost=2 Card=4 Bytes=48)
   4    2       TABLE ACCESS (FULL) OF 'TEST_OBJECT' (TABLE) (Cost=2 Card=82 Bytes=1558)
   5    1   NESTED LOOPS (Cost=5 Card=3 Bytes=93)
   6    5       TABLE ACCESS (FULL) OF 'TEST_OBJ1' (TABLE) (Cost=2 Card=4 Bytes=48)
   7    5       TABLE ACCESS (FULL) OF 'TEST_OBJECT' (TABLE) (Cost=1 Card=1 Bytes=19)
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