zhangsk 发表于 2013-1-27 05:42:03

How does Java compiler resolve the ambiguity to decide which

转http://bobcat.webappcabaret.net/javachina/faq/01.htm#lan_Q120
Q. How does Java compiler resolve the ambiguity to decide which methods to call?
A:
In the following example, four test() methods, if we pass ambiguous \b{null} to the test, which one should (will) be called? The 3 on top has super/subclass/sub-subclass relationship. The most specific one (down hierarchy) will be called. The 4th with String as a parameter, but it is a sibling of Tester. Ambiguity compile time error results.

package com.zsk.testnull;class Tester {   void test(Object s)    { System.out.println ("Object version");    }   void test(Tester s)    { System.out.println ("Tester version");    }   void test(SubTester s) { System.out.println ("SubTester version"); }    // Not compilable any more if you uncomment the line   // since String and Tester are siblings//   void test(String s) { System.out.println ("String version"); }    public static void main (String args[]) {   Tester c = new Tester ();   // Ambiguous, the most specific one which fit will be call    c.test (null);         // SubTester version   c.test (new Object()); // Object version   } }class SubTester extends Tester{ }

"The informal intuition is that one method declaration is more specific than another if any invocation handled by the first method could be passed on to the other one without a compile-time type error." Quotation from JLS2
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