yefishskivvy 发表于 2013-1-26 12:57:36

简单算法

简单算法如下, 核心思路是值域有限,转化成反函数

bool isUsedByA = {0};
bool isUsedByB = {0};

for each value in a[]
begin
    isUsedByA = true;
end

for each char_elem in b[]
begin
    isUsedByB = true;
end

define buffer c
step idx from 0 to 255
begin
    if (isUsedByA && !isUsedByB)
    {
        c.push_back(idx);
    }
end
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