创建多线程做减法(简化2）（修改）
对上一次写得再修改，修正了部分问题，但是无法处理过大线程数，可能是系统资源分配问题代码如下：
#include <pthread.h>#include <stdio.h>#include <stdlib.h>#define SIZE 6int sum;static pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;static pthread_cond_t cond = PTHREAD_COND_INITIALIZER;void * thread(void *);int main(int argc, char *argv[]){ pthread_t tid; int i, rc = {0, 0, 0, 0, 0}; printf("enter main\n"); printf("Please input a number : \n"); scanf("%d", &sum); while (sum >= 0) {for (i = 1; i < SIZE; i++){ int * argzone = malloc((int)sizeof(int)); *argzone = i; rc = pthread_create(&tid, NULL, thread, argzone); if (rc != 0) printf("The thread%d-create is failed!\n", i); }//pthread_mutex_lock(&mutex);pthread_cond_wait(&cond, &mutex);//pthread_mutex_unlock(&mutex); } printf("leave main\n"); exit(0);}void * thread(void *arg){ int * nArg = (int *)arg; printf("enter thread%d\n", *nArg); pthread_mutex_lock(&mutex); if (sum <= 0)exit(0); elseprintf("This is thread%d, sum : %d, thread id is %u\n", *nArg, sum, (unsigned int)pthread_self()); pthread_cond_signal(&cond); sum -= (*nArg); printf("This is thread%d, sum : %d, thread id is %u\n", *nArg, sum, (unsigned int)pthread_self()); pthread_mutex_unlock(&mutex); printf("leave thread%d\n", *nArg); pthread_exit(0);}
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